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0.05x^2+55x-10000=0
a = 0.05; b = 55; c = -10000;
Δ = b2-4ac
Δ = 552-4·0.05·(-10000)
Δ = 5025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{5025}=\sqrt{25*201}=\sqrt{25}*\sqrt{201}=5\sqrt{201}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(55)-5\sqrt{201}}{2*0.05}=\frac{-55-5\sqrt{201}}{0.1} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(55)+5\sqrt{201}}{2*0.05}=\frac{-55+5\sqrt{201}}{0.1} $
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